.5/3.14=r^2

Solution for .5/3.14=r^2 equation:

.5/3.14=r^2

We move all terms to the left:

.5/3.14-(r^2)=0

We add all the numbers together, and all the variables

-1r^2+.5/3.14=0

We multiply all the terms by the denominator


-1r^2*3.14+.5=0

We add all the numbers together, and all the variables

-1r^2*3.14+0.5=0

Wy multiply elements

-3.14r^2+0.5=0

a = -3.14; b = 0; c = +0.5;
Δ = b2-4ac
Δ = 02-4·(-3.14)·0.5
Δ = 6.28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{6.28}}{2*-3.14}=\frac{0-\sqrt{6.28}}{-6.28}
=-\frac{\sqrt{}}{-6.28}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{6.28}}{2*-3.14}=\frac{0+\sqrt{6.28}}{-6.28}
=\frac{\sqrt{}}{-6.28}
$